Using a converging lens ,an object is placed at distance less than f from the lensimages as
To understand how a converging lens forms images, we need to consider a few concepts and equations.
1. Lens equation: The lens equation relates the object distance (u), image distance (v), and the focal length (f) of the lens. It is given by:
1/u + 1/v = 1/f
Here, u is negative for objects placed before the lens, v is positive for real images formed on the opposite side of the lens, and f is positive for converging lenses.
2. Magnification: The magnification (M) of a lens gives us the ratio of the image height to the object height. It is given by:
M = -v/u
Magnification can be positive or negative, depending on whether the image formed is upright or inverted.
Now, let's consider the scenario where the object is placed at a distance less than the focal length (f) from the converging lens.
This situation is called "object placed within the focal length" or "object at a distance less than f".
In this case, the image formed by the lens is virtual, upright, and magnified. It is located on the same side as the object.
To determine the image distance (v) and magnification (M), we can use the lens equation and magnification formula.
Since the object is placed at a distance less than the focal length (u < f), the lens equation becomes:
1/u + 1/v = 1/f
We know that u is negative, f is positive for converging lenses, and u < f.
Using this equation, we can solve for v to find the image distance.
To find the magnification, we can use:
M = -v/u
Substituting our determined value for v, we can calculate the magnification.
Remember to use proper units and sign conventions as per the equations.
I hope this explanation helps you understand how to determine the image formed by a converging lens when the object is placed at a distance less than the focal length.