In a thermonuclear device, the pressure of 0.050 liters of gas within the bomb casing reaches 4.0 x 106 atm. When the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm. What is the volume of the gas after the explosion?
To solve this problem, we can make use of the combined gas law, which states that the product of pressure and volume divided by temperature is constant for a given amount of gas:
(P1 × V1) / T1 = (P2 × V2) / T2
Where:
P1 and P2 are the initial and final pressures
V1 and V2 are the initial and final volumes
T1 and T2 are the initial and final temperatures
In this case, the initial pressure (P1) is 4.0 x 10^6 atm, the initial volume (V1) is 0.050 liters, and the final pressure (P2) is 1.00 atm.
Since the gas is released into the atmosphere, we can assume that the final volume (V2) will be the sum of the initial volume (V1) and the volume of the bomb casing (since they would both be released together).
Therefore, V2 = V1 + volume of bomb casing
Unfortunately, the volume of the bomb casing is not provided in the question. Therefore, we cannot determine the exact final volume.
So, to obtain a numerical answer, we need to know the volume of the bomb casing. Without that information, we can only provide a general formula but not an exact value.
Use P1V1 = P2V2
p1 = 4E6 atm
v1 = 0.05 L
p2 = 1 atm
v2 = ?