an ac generator has 20 turns of wire of area 0.16 m2. The loop rotates in a magnetic field of 0.52 T at a frequency of 80 Hz. Find the maximum induced emf.

To find the maximum induced electromotive force (emf) in an AC generator, you can use Faraday's law of electromagnetic induction, which states that the magnitude of the induced emf is given by the equation:

emf = NABωsin(ωt)

Where:
- emf is the induced electromotive force (in volts)
- N is the number of turns of wire
- A is the area of the loop (in square meters)
- B is the magnetic field strength (in tesla)
- ω is the angular velocity (in radians per second)
- t is the time (in seconds)

Let's plug in the values given:

N = 20 turns
A = 0.16 m^2
B = 0.52 T
ω = 2πf (where f is the frequency, given as 80 Hz)
t is not specified, but we are interested in the maximum induced emf, which occurs at t = 0.

First, let's calculate ω:

ω = 2πf = 2π * 80 Hz = 160π rad/s

Now, let's plug in all the values into the equation:

emf = 20 turns * 0.16 m^2 * 0.52 T * 160π rad/s * sin(0)
= 20 * 0.16 * 0.52 * 160π * 0
= 0

Therefore, the maximum induced emf is 0 volts.