Hookes law states that the force , F in a spring extended by length x is given by F=-Kx. According to Newton's second law F=ma, where m is the mass and a is the acceleration. Calculate the dimension of the spring constant k.

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  1. -K x = m a

    -K ⋅ meters = kg ⋅ m/s^2 = Newtons

    K = - N / m

    the spring force increases linearly (directly proportional to the stretch)
    ... in the direction opposite the elongation (stretching)

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