60cm^3 of oygen diffuses through a porous pot in 50seconds.How long would it take 60cm^3 of oxgen gas diffuses through a porous pot in 50sec.How long would it take 60cm^3 of sulphur(iv)oxide to diffuse through the same pot under the same conditions?
rate O2 = 60 cc/50 sec = 1.2 cc/sec. molar mass O2 = 32
rate SO2 = 60 cc/x sec molar mass SO2 = 64
(rate O2/rate SO2) = sqrt(molar mass SO2/molar mass O2)
Substitute and solve for x = seconds for SO2
Post your work if you get stuck.