What is the value of equilibrium constant kc for NO2 + N2O =3NO..Given that equilibrium concentration are NO2=1.25, N2O=1.80 and NO=0.0015
kc = [NO]^3 / ([NO2] [N2O])
WHAT IS THE VALUE OF THE EQUILIBRIUM CONSTANT,KC,FOR NO2 + N2O =3NO
GIVVEN THE THE EQUILIBRIUM CONCENTRATION ARE NO2=1.25M, N2O=1.80M, AND NO=0.0015
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To calculate the equilibrium constant Kc for the given reaction NO2 + N2O → 3NO, you need to use the concentrations of the species involved in the reaction at equilibrium.
The equation for the equilibrium constant Kc in terms of concentrations is:
Kc = ([NO]^3) / ([NO2] * [N2O])
Using the given concentrations at equilibrium:
[NO2] = 1.25
[N2O] = 1.80
[NO] = 0.0015
Substituting these values into the equation for Kc:
Kc = ((0.0015)^3) / (1.25 * 1.80)
Simplifying the equation:
Kc = 0.000003375 / 2.25
Kc ≈ 0.0000015
So, the value of the equilibrium constant Kc for the given reaction is approximately 0.0000015.