A construction company penalizes each day of delay in construction of a bridge. The penalty will be $4500 for the first day and will increase by $12000 for each following day. Based on the budget, the company can afford to pay a maximum of $155000 towards penalty. By using arithmetic progression, find the maximum amount of data the construction of the bridge can be delayed.
You have an AP with
a = 4500
d = 12000
So you need to find n for which
n/2 (2*4500 + (n-1)*12000) <= 155000