Given that the HCF of a pair of different numbers is 8, find the two numbers if both numbers are less than 20
well, 8 and 16 come to mind
Are you sure that this is the right answer??, I am trusting you with this my friend, but if it is wrong I will tell everyone to never trust you ever again.
Also is your name Antonio something...,(Tony) if it is you are such a scammer if it is not your in luck.
Anyways bye, hope for this answer to be right, see ya. Bye Thanks.
To find the two numbers with a highest common factor (HCF) of 8 and both numbers being less than 20, we need to find two numbers that are less than 20 and have factors of 8.
The factors of 8 are 1, 2, 4, and 8. Since the HCF is given as 8, both numbers must be divisible by 8.
Let's list the numbers less than 20 that are divisible by 8:
8, 16.
Since the two numbers have to be different, the pair of integers that satisfies the given conditions is (8, 16).
To find the two numbers whose highest common factor (HCF) is 8, we need to determine the possible pairs of numbers that are less than 20 and have 8 as their highest common factor. Here's how you can find these numbers:
Step 1: Make a list of all the numbers less than 20.
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19
Step 2: Identify the pairs of numbers that have 8 as their highest common factor.
From the list, we can see that there are a few pairs whose highest common factor is 8:
(8, 16)
(16, 8)
Step 3: Verify that these pairs are correct.
To confirm that these pairs indeed have 8 as their HCF, we can use the Euclidean Algorithm to calculate the HCF of each pair.
For the pair (8, 16):
- Divide 16 by 8: 16 ÷ 8 = 2
- The remainder is 0, so the HCF is 8.
For the pair (16, 8):
- Divide 8 by 16: 8 ÷ 16 = 0.5
- Since we are working with whole numbers, we can ignore the decimal part.
- The remainder is 8, so the HCF is 8.
Step 4: Final answer
The two numbers whose HCF is 8 and are both less than 20 are 8 and 16.