A bicycle pump contains 250 cm3 of air at a pressure of 90 KPa. If the air is compressed, the volume is reduced to 200 cm3. What is the pressure of the air inside the pump?
use p1v1 = p2v2
V1 = 90 and V2 =
P1= 250 cm and p9= 200
P1V1 = p2V2
V2=p1V1/p2
V2=250cm3x90kpa/200cm3 =
V2=
You need to read the problem again.
V1 = 250 cc
V2 = 200 cc
P1 = 90 kPa
P2 = ?
To find the pressure of the air inside the pump, you can use the formula: p1v1 = p2v2.
Given:
V1 = 250 cm^3 (initial volume)
V2 = 200 cm^3 (final volume)
P1 = 90 kPa (initial pressure)
To find P2 (final pressure), we can rearrange the formula:
P2 = (P1 * V1) / V2
Substituting the values:
P2 = (90 kPa * 250 cm^3) / 200 cm^3
Now, we can calculate P2:
P2 = (22500 kPa*cm^3) / 200 cm^3
Simplifying,
P2 = 112.5 kPa
Therefore, the pressure of the air inside the pump is 112.5 kPa.