if a spring has a stiffness of 950n/m what work will be done in extending the spring by 60mm
work = (1/2) k x^2
=(1/2)(950 Newtons/meter) (60*10^-3 meters)^2
= 1.7*10^6*10^-6 = 1.7 Newton meters = 1.7 Joules
Bolatito
To calculate the work done in extending a spring, you can use the formula:
Work = (1/2) * k * x^2
where:
- Work is the work done (in joules, J)
- k is the stiffness constant of the spring (in newtons per meter, N/m)
- x is the displacement or extension of the spring (in meters, m)
In this case, the stiffness of the spring is given as 950 N/m, and the extension is 60 mm, which is equivalent to 0.06 meters.
Substituting the given values into the formula:
Work = (1/2) * 950 N/m * (0.06 m)^2
Work = 0.5 * 950 N/m * (0.0036 m^2)
Work = 0.5 * 950 N/m * 0.0036 m^2
Work ≈ 1.713 joules (J)
Therefore, the work done in extending the spring by 60 mm is approximately 1.713 joules.
To find the work done in extending a spring, you can use the formula:
Work = (1/2) k x^2
Where:
- Work is the work done (in joules)
- k is the stiffness of the spring (in newtons per meter, N/m)
- x is the extension of the spring (in meters)
In this case, the stiffness of the spring (k) is given as 950 N/m, and the extension (x) is given as 60 mm, which is equivalent to 0.06 meters.
Plugging the values into the formula:
Work = (1/2) * 950 N/m * (0.06 m)^2
= (1/2) * 950 N/m * 0.0036 m^2
= 1.71 joules (rounded to two decimal places)
Therefore, the work done in extending the spring by 60 mm is approximately 1.71 joules.