Calculate the number of moles of gas with a volume of 70 L at a temperature of 65 °C and pressure of 2.4 atm.

6.05?

Well, if you want an actual answer instead of an approximation, let's do some calculations. To calculate the number of moles of gas, we can use the ideal gas law equation, PV = nRT.

First, let's convert the temperature from Celsius to Kelvin. The formula for converting Celsius to Kelvin is K = °C + 273.15. So, 65 °C + 273.15 = 338.15 K.

Now, let's rearrange the ideal gas law equation to solve for n: n = PV / RT.

Substituting the given values: n = (2.4 atm)(70 L) / (0.0821 L·atm/(mol·K))(338.15 K)

Using a calculator, we can find that the number of moles of gas is approximately 5.426 moles.

So, it seems like my initial approximation of 6.05 was off by a bit. I must have been clowning around with that one!

To calculate the number of moles of gas, we can use the Ideal Gas Law equation:

PV = nRT

Where:
P = pressure of the gas (in atm)
V = volume of the gas (in liters)
n = number of moles of the gas
R = Ideal Gas Constant (0.0821 L.atm/mol.K)
T = temperature of the gas (in Kelvin)

First, we need to convert the temperature from Celsius to Kelvin. The conversion formula is:

K = °C + 273.15

So, let's convert the temperature:

Temperature in Kelvin:
65 °C + 273.15 = 338.15 K

Now, we can plug the values into the equation:

2.4 atm * 70 L = n * (0.0821 L.atm/mol.K) * 338.15 K

168 = 27.455 * n

Divide both sides by 27.455 to solve for n:

n = 168 / 27.455
n ≈ 6.124 moles

Therefore, the number of moles of gas in a volume of 70 L at a temperature of 65 °C and a pressure of 2.4 atm is approximately 6.124 moles.

To calculate the number of moles of a gas, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure in atm
V = volume in liters
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature in Kelvin (K)

First, we need to convert the temperature from Celsius to Kelvin. To do this, we add 273.15 to the given temperature:

65 °C + 273.15 = 338.15 K

Now we can plug in the values into the equation and solve for n:

(2.4 atm) * (70 L) = n * (0.0821 L·atm/(mol·K)) * (338.15 K)

168 atm·L = 27.20229 n

Dividing both sides by 27.20229 gives us:

n = 6.1667 moles

Therefore, the number of moles of gas with a volume of 70 L at a temperature of 65 °C and pressure of 2.4 atm is approximately 6.17 moles, rounded to two decimal places.

I didn't work it out but you use PV = nRT