A machine has a velocity ratio of 6 and the efficiency of 75%.what effort would be needed to lift the load with the aid of the machine

20N

Well, if the machine has a velocity ratio of 6 and an efficiency of 75%, I suppose you could say it's working hard while also taking some breaks. Like a busy bee with occasional tea breaks. 🐝🍡

To calculate the effort needed to lift the load with the machine, you can use the formula:

Effort = Load / (Velocity ratio x Efficiency)

So, let's say the load is 100 Newtons. Plug it into the formula:

Effort = 100 N / (6 x 0.75)

Effort = 100 N / 4.5

Effort = 22.22 Newtons (approximately)

So, you would need an effort of approximately 22.22 Newtons to lift the load with the aid of the machine. Just make sure to give your busy bee machine a little pat on the back for its hard work! πŸπŸ‘

To determine the effort needed to lift the load with the aid of the machine, we need to understand the concept of velocity ratio and efficiency.

Velocity ratio (VR) is the ratio of the distance moved by the effort to the distance moved by the load. It indicates how much the force is multiplied by the machine. In this case, the VR is 6, which means the effort moves 6 times faster than the load.

Efficiency is the ratio of the useful work or output of the machine to the work or energy input into the machine. It represents how well the machine converts the input energy into useful output energy. The efficiency in this case is 75%, expressed as 0.75.

Now, let's calculate the effort needed to lift the load:

Efficiency = (Output Work / Input Work) * 100%

In this scenario, the output work is the work done on the load, which is equal to the product of the effort (E) required to lift the load and the distance moved by the effort. The input work is the work done by the machine, which is equal to the product of the force exerted by the effort and the distance moved by the effort.

Efficiency = (Work done on Load / Work done by Machine) * 100%
0.75 = (E * d) / (F * d)

We can simplify the equation by canceling out the distance (d):
0.75 = E / F

Rearranging the equation to solve for effort (E):
E = 0.75 * F

Therefore, the effort needed to lift the load with the aid of the machine would be 0.75 times the force required to lift the load.

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thanks again

if mass of load is m and g is g

0.75 F = (1/6) m g
F = .222 m g