The mass of a sheet of metal varies jointly with its area and its thickness.A sheet of metal of area 250 cm square and thickness 1 mm has a mass of 200 g.
(a) Find the formula which connects the mass Mg,the area A cm square and the thickness t mm.
(b) Hence find the mass of a piece of metal of area 400 cm square and thickness 3 mm
m = kat
200 = k*250*1
Now you can figure k, and thus answer the questions
Please I need an answer
Yes
I need an answer
M=ka/t
200g=250cmk/250
K =0.8
I need a straight answer no how to only find constant
Ogun go kill you all I need answer
To find the formula connecting the mass Mg, area A cm square, and thickness t mm, we can use the concept of direct variation. In direct variation, two variables are directly proportional to each other, meaning they increase or decrease together at a constant rate.
Let's denote the constant of variation as k. Based on the given information, we can form the equation:
Mg = k * A * t
where Mg represents the mass in grams, A is the area in cm square, and t is the thickness in mm.
Now, we can use the given values to solve for k.
Given: Mg = 200 g, A = 250 cm square, and t = 1 mm
Substituting these values into the equation, we get:
200 = k * 250 * 1
Simplifying this, we find:
k = 200 / (250 * 1) = 0.8 g/cm^2*mm
Therefore, the formula connecting the mass Mg, area A cm square, and thickness t mm is:
Mg = 0.8 * A * t
Now, let's move on to part (b) where we need to find the mass of a piece of metal with area 400 cm square and thickness 3 mm.
Using the formula we derived in part (a), we have:
Mg = 0.8 * A * t
Substituting A = 400 cm square and t = 3 mm, we get:
Mg = 0.8 * 400 * 3
Simplifying this expression, we find:
Mg = 960 g
Therefore, the mass of the piece of metal with an area of 400 cm square and thickness of 3 mm is 960 g.