a. 5(z + 1) = 3(z + 2) + 11 Solve for Z
b. 7(x+4)-2[x-3(5+x)]=2/3(x-6)
No, you don't get a)
here is what you should have:
5(z + 1) = 3(z + 2) + 11
5z + 5 = 3z + 6 + 11
5z - 3z = 17 - 5
2z = 12
z = 6
b)
7(x+4)-2[x-3(5+x)]=2/3(x-6)
inner brackets first
7(x+4)-2[x-15-3x]=2/3(x-6)
simplify and do the front while at it
7x + 28 - 2[-2x - 15] = 2/3(x-6)
do the square bracket
7x + 28 + 4x + 30 = 2/3(x-6)
simplify the left
11x + 58 = 2/3(x-6)
multiply every term by 3 to clear that fraction
33x + 174 = 2(x-6)
33x + 174 = 2x - 12
33x - 2x = -12 - 174
31x = -186
divide both sides by 31
x = -6
Once you understand how to do these, and have done about 50 of them,
you can really reduce the number of steps to about 4
Who are all those different "Sofa's" ?
You must know how to do these simple equations,
show me your first few steps, so I can see where your difficulties are
It's my sisters
a. 5z + 1= 3z + 2 + 11 i think i get this question but i don't understand b.
thank you
a. To solve the equation 5(z + 1) = 3(z + 2) + 11 for z, we need to simplify both sides of the equation by distributing and combining like terms.
Let's start by distributing on both sides:
5z + 5 = 3z + 6 + 11
Next, we can combine like terms on the right side:
5z + 5 = 3z + 17
Now, let's isolate the variable z by subtracting 3z from both sides:
5z - 3z + 5 = 3z - 3z + 17
2z + 5 = 17
Finally, subtract 5 from both sides to get z alone:
2z + 5 - 5 = 17 - 5
2z = 12
To get the value of z, we divide both sides by 2:
2z/2 = 12/2
z = 6
Therefore, the solution to the equation 5(z + 1) = 3(z + 2) + 11 is z = 6.
b. To solve the equation 7(x+4)-2[x-3(5+x)] = (2/3)(x-6) for x, we follow a similar process.
Let's start by simplifying each side of the equation:
7x + 28 - 2[x - 15 - 3x] = (2/3)(x-6)
Simplify the expression inside the brackets using the distributive property:
7x + 28 - 2[-x + 15 - 3x] = (2/3)(x-6)
7x + 28 + 2x - 30 + 6x = (2/3)(x-6)
Combine like terms on both sides:
15x - 2 = (2/3)(x-6)
To remove the fraction on the right side, we can multiply both sides of the equation by 3:
(3)(15x - 2) = (3)(2/3)(x-6)
45x - 6 = 2(x - 6)
Now, distribute on both sides:
45x - 6 = 2x - 12
Next, subtract 2x from both sides:
45x - 2x - 6 = 2x - 2x - 12
43x - 6 = -12
Add 6 to both sides:
43x - 6 + 6 = -12 + 6
43x = -6
Finally, divide both sides by 43:
43x/43 = -6/43
x = -6/43
So, the solution to the equation 7(x+4)-2[x-3(5+x)] = (2/3)(x-6) is x = -6/43.