Three designs are proposed for an engine that is to operate between 500 and 300 K. Design A is claimed to produce 750 J of work per kilojoule of heat input, B is claimed to produce 500 J, and C is claimed to produce 250J. Which design would you choose?
efficiency=(500-300)/300=.67
work output= 1000*eff=670 J
so the first design A is baloney
so go with design B would be my choice.
what formula did u use?
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To determine which design to choose, we need to calculate the thermal efficiency (η) of each design. Thermal efficiency is defined as the ratio of work output to heat input.
Thermal Efficiency (η) = Work output / Heat input
For Design A:
Thermal Efficiency (η_A) = 750 J / 1000 J = 0.75
For Design B:
Thermal Efficiency (η_B) = 500 J / 1000 J = 0.5
For Design C:
Thermal Efficiency (η_C) = 250 J / 1000 J = 0.25
From the calculations, we can see that Design A has the highest thermal efficiency (0.75), followed by Design B (0.5), and Design C (0.25).
Therefore, Design A would be the preferred choice as it produces the highest amount of work per kilojoule of heat input.