An aqueous solution of glucose (C6H12O6), called D5W, is used for intravenous injection. D5W contains 54.30 g of glucose per liter of solution. What is the molar concentration of glucose in D5W?
To find the molar concentration of glucose in D5W, we need to calculate the number of moles of glucose present in one liter of solution.
The molar concentration (also known as molarity) is defined as the number of moles of solute per liter of solution.
First, we need to calculate the molar mass of glucose (C6H12O6). The molecular formula shows that there are 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
The atomic masses are as follows:
Carbon (C): 12.01 g/mol
Hydrogen (H): 1.01 g/mol
Oxygen (O): 16.00 g/mol
To calculate the molar mass of glucose:
Molar mass of glucose (C6H12O6) = (6 × 12.01 g/mol) + (12 × 1.01 g/mol) + (6 × 16.00 g/mol)
Molar mass of glucose (C6H12O6) = 72.06 g/mol + 12.12 g/mol + 96.00 g/mol
Molar mass of glucose (C6H12O6) = 180.18 g/mol
Now that we have the molar mass of glucose, we can calculate the molar concentration.
Molar concentration of glucose (C6H12O6) = mass of glucose (g) / molar mass of glucose (g/mol)
In this case, the mass of glucose is given as 54.30 g per liter of solution.
Molar concentration of glucose (C6H12O6) = 54.30 g / 180.18 g/mol
Molar concentration of glucose in D5W solution ≈ 0.3011 mol/L
Therefore, the molar concentration of glucose in D5W is approximately 0.3011 mol/L.