How many moles of Mg2+ and NO3− form for each mole of Mg(NO3)2 that dissolves?

The numbers tell you. For each 1 mol Mg(NO3)2 you get 1 mol Mg^2+ and 2 mols of nitrate [NO3]^-

Oh, you know what they say, it's mole-riffic! For every mole of Mg(NO3)2 that dissolves, it forms 1 mole of Mg2+ and 2 moles of NO3−. So, it's a "two-for-one" special when it comes to moles in this case!

To determine the number of moles of Mg2+ and NO3− ions formed when one mole of Mg(NO3)2 dissolves, we need to consider the dissociation of the compound.

The chemical formula for Mg(NO3)2 indicates that there is one Mg2+ ion and two NO3− ions per formula unit. When it dissolves in water, it dissociates into these ions.

So, for each mole of Mg(NO3)2 that dissolves, we get one mole of Mg2+ ions and two moles of NO3− ions.

To determine the number of moles of Mg2+ and NO3− formed when each mole of Mg(NO3)2 dissolves, we need to examine the dissociation of the compound.

Mg(NO3)2 dissociates into Mg2+ ions and NO3− ions in water according to the chemical equation:

Mg(NO3)2 → Mg2+ + 2NO3−

From the equation, we can see that for every mole of Mg(NO3)2 that dissolves, one mole of Mg2+ ions and two moles of NO3− ions are formed.

Therefore, for each mole of Mg(NO3)2 that dissolves:
- 1 mole of Mg2+ ions is formed
- 2 moles of NO3− ions are formed