If a load of 1kg stretched a cord by 1.2cm, what is the force constant of the cord ?. ( g=10m/s2) *
K = mg/d = 1*10/1.2 = 8.33 N/cm.
Well, if you're looking for the force constant of the cord, also known as the spring constant, we're going to have to do a little math. Are you ready to put your thinking cap on?
Okay, here we go! We know that the weight of the load is equal to the force of the spring. So we can set up an equation like this:
Force of the spring = weight of the load
Now, the weight of the load is given by the formula: weight = mass × acceleration due to gravity
Since the load is 1kg and the acceleration due to gravity is 10m/s^2, we have:
Weight of the load = 1kg × 10m/s^2 = 10N
Now we can substitute this value into our equation:
Force of the spring = 10N
But we also know that the force of the spring can be calculated using Hooke's Law, which states that the force of a spring is directly proportional to the displacement from its equilibrium position. In this case, the displacement is given as 1.2cm, which we'll need to convert to meters by dividing it by 100:
Displacement = 1.2cm ÷ 100 = 0.012m
So our equation becomes:
Force of the spring = spring constant × displacement
We can rearrange the equation to solve for the spring constant:
Spring constant = Force of the spring ÷ displacement
Plugging in the values we know:
Spring constant = 10N ÷ 0.012m
Now, if I did my math right, the spring constant should be...
*Drumroll please*
Around 833.33 N/m! Give or take a few giggles.
To find the force constant of the cord, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.
Hooke's Law equation: F = k * x
Where:
F is the force applied to the cord
k is the force constant (also known as spring constant)
x is the displacement of the cord
Given:
Load = 1kg
Displacement = 1.2cm = 0.012m
g = 10m/s^2
We need to find the force constant (k).
From Newton's second law, we know that force is equal to the mass multiplied by the acceleration. The acceleration of an object due to gravity is given by g (acceleration due to gravity).
So, F = m * g
F = 1kg * 10m/s^2
F = 10N
Now, we can use Hooke's Law to find the force constant (k):
10N = k * 0.012m
Solving for k:
k = 10N / 0.012m
k ≈ 833.33 N/m
Therefore, the force constant of the cord is approximately 833.33 N/m.
To find the force constant of the cord, we can use Hooke's Law, which states that the force needed to stretch or compress a spring or a cord is directly proportional to the displacement from its equilibrium position.
Hooke's Law can be written as follows:
F = k * x
Where F is the force applied, k is the force constant (also known as the spring constant), and x is the displacement from the equilibrium position.
In this case, we have a load of 1kg and it stretches the cord by 1.2cm. First, we need to convert the displacement into SI units, which is meters.
1.2cm = 0.012m
Now, we can rearrange the equation to solve for the force constant:
k = F / x
The force acting on the cord can be calculated using Newton's second law of motion:
F = m * g
Where m is the mass and g is the acceleration due to gravity. Given that the mass is 1kg and g is 10 m/s^2, we can calculate the force:
F = 1kg * 10m/s^2 = 10N
Now, we can substitute the values into the equation for the force constant:
k = 10N / 0.012m
k ≈ 833.33 N/m
Therefore, the force constant of the cord is approximately 833.33 N/m.