In the country of United States of Heightlandia, the height measurements of ten-year-old children are approximately normally distributed with a mean of 55.7 inches, and standard deviation of inches.
What is the probability that a randomly chosen child has a height of more than 54.7 inches?
I got 0.648 and it’s wrong I’m not sure how though
You can play around with Z table stuff at
davidmlane.com/hyperstat/z_table.html
To find the probability that a randomly chosen child has a height of more than 54.7 inches, you need to calculate the area under the normal distribution curve to the right of 54.7 inches.
To do this, we can use standardization, also known as the z-score. The formula to calculate the z-score is:
z = (x - μ) / σ
where:
z is the z-score,
x is the value you want to find the probability of (54.7 inches in this case),
μ is the mean of the distribution (55.7 inches in this case), and
σ is the standard deviation of the distribution.
Using the given values, we can calculate the z-score:
z = (54.7 - 55.7) / σ
Now, you have mentioned that the standard deviation is missing in your question. Please provide the standard deviation value so that we can calculate the correct probability.