a)How many calcium ions are in 2.17 moles of calcium phosphate?
b)If 1.41 g of zinc or attitude 1.85 g of hydrochloric acid identify the limiting and excess reagents give reasons for your choice and determine how many moles of the excess reagent remains
c)What volume of 0.125 mol/L sodium hydroxide solution is required to completely react with 15.0 mL of 0.100 mol/L silver sulfate? give your answer in millilitres
a)How many calcium ions are in 2.17 moles of calcium phosphate?
2.17 mols Ca3(PO4)2 has 2.17 x 3 = 6.51 mols Ca ions. 1 mole of any ion contains 6.02E23 individual ions.
b)If 1.41 g of zinc (you must have meant "are added to) 1.85 g of hydrochloric acid identify the limiting and excess reagents give reasons for your choice and determine how many moles of the excess reagent remains
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = g/atomic mass = 1.41/65.4 = 0.021 estimated. You need to redo it.
mols HCl = 1.85/36.5 = estimated 0.05.
How many mols H2 could each produce? For Zn that's
0.021 mols H2. For HCl that's 0.05 x 1/2 = 0.025. Therefore, the smaller amount will be formed; i.e., 0.021 mols H2 will form, Zn is the limiting reagent (LR) and the Excess reagent (ER) is HCl.
If we used all 0.021 mols Zn, we will use 2*0.021 = 0.042 mols HCl and 0.05 - 0.042 = ? mols HCl, the ER, remain un-reacted.
c)What volume of 0.125 mol/L sodium hydroxide solution is required to completely react with 15.0 mL of 0.100 mol/L silver sulfate? give your answer in millilitres.
You don't show a reaction, The following is just ONE that can be written.
2NaOH + Ag2SO4 ==> 2AgOH +Na2SO4. The AgOH is not stable but I'll leave it at that.
mols Ag2SO4 = M x L = 0.1 x 0.015 L = 0.0015
0.0015 mols Ag2SO4 will required twice that or 0.0030 mols NaOH. Then M mols/L. You know mols and M of NaOH, substitute and solve for L and convert to mL.
Post your work if you run into a problem.
a) To determine the number of calcium ions in 2.17 moles of calcium phosphate, we need to use the chemical formula and stoichiometry.
The chemical formula for calcium phosphate is Ca3(PO4)2. From the formula, we can see that for every Ca3(PO4)2 molecule, there are 3 calcium ions (Ca2+).
First, we need to calculate the number of moles of calcium ions in 2.17 moles of calcium phosphate.
Number of moles of calcium ions = 3 moles of calcium ions/mole of calcium phosphate * 2.17 moles of calcium phosphate
b) To identify the limiting and excess reagents in a chemical reaction, we need to compare the stoichiometry and molar ratios of the reactants.
1 mole of zinc (Zn) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of zinc chloride (ZnCl2).
First, we need to convert the given grams of each reactant to moles using their respective molar masses.
Molar mass of zinc (Zn) = 65.38 g/mol
Molar mass of hydrochloric acid (HCl) = 36.46 g/mol
For 1.41 g of zinc:
Number of moles of zinc = 1.41 g / 65.38 g/mol
For 1.85 g of hydrochloric acid:
Number of moles of hydrochloric acid = 1.85 g / 36.46 g/mol
Next, we need to calculate the mole ratio of zinc to hydrochloric acid based on the balanced chemical equation.
Mole ratio of zinc to hydrochloric acid = 1 mole of zinc / 2 moles of hydrochloric acid
If the mole ratio of zinc to hydrochloric acid is less than the actual ratio calculated from the masses of the reactants, then zinc is the limiting reagent. Otherwise, hydrochloric acid is the limiting reagent.
Finally, to determine how many moles of the excess reagent remain, we can subtract the moles of the limiting reagent used from the moles of the excess reagent initially present.
c) To calculate the volume of sodium hydroxide (NaOH) solution required to completely react with a given amount of silver sulfate (Ag2SO4), we need to use the stoichiometry of the balanced chemical equation and given concentrations of the reactants.
The balanced chemical equation for the reaction between sodium hydroxide and silver sulfate is:
2 NaOH + Ag2SO4 -> 2 Na2SO4 + 2 AgOH
From the equation, we can see that the mole ratio of sodium hydroxide to silver sulfate is 2:1.
First, calculate the number of moles of silver sulfate using its molar concentration and volume:
Number of moles of silver sulfate = 0.100 mol/L * 0.015 L
Next, using the mole ratio from the balanced chemical equation, we can determine the number of moles of sodium hydroxide required to react with the calculated moles of silver sulfate.
Number of moles of sodium hydroxide = 2 * number of moles of silver sulfate
Finally, to calculate the volume of the sodium hydroxide solution, we can divide the number of moles of sodium hydroxide by its molar concentration:
Volume of sodium hydroxide solution = (Number of moles of sodium hydroxide) / (0.125 mol/L)
The answer would be given in milliliters as requested.