Iupac name of Cr(CN3)Cl3
And [Co(NH3)Cl(NH3)]Cl
I disagree with both of these names. I would name them this way. I assume the CN^- and Cl^- are in the coordination sphere for the first one although it isn't enclosed in parentheses so
trichlorotricyanochromium(VI)
diamminechlorocobalt(II) chloride
Cr(CN3)Cl3: tricyanochroniumchlorovi
[Co(NH3)Cl(NH3)]Cl: Hexaamminecobalt(III) chloride
Ipuacname
To find the IUPAC name of a compound, we need to follow a specific nomenclature for coordination compounds.
1. Cr(CN3)Cl3:
First, we need to identify the central metal atom, which is chromium (Cr). Then, we count the total number of ligands bonded to the central metal atom. In this case, there are three chloride ligands (Cl) and three cyanide ligands (CN^-).
To name this compound:
- Start with the name of the central metal atom: chromium.
- Add the oxidation state of the central metal atom as a Roman numeral in parentheses: chromium(III).
- Write the names of the ligands in alphabetical order.
- Use prefixes to indicate the number of each ligand, if necessary.
- Use a comma to separate each ligand name.
Therefore, the IUPAC name of this compound is trichloridetris(cyanido)chromium(III).
2. [Co(NH3)Cl(NH3)]Cl:
Here, we have a complex with the central metal atom cobalt (Co), one chloride ligand (Cl), and two ammonia ligands (NH3).
To name this compound:
- Start with the name of the central metal atom: cobalt.
- Add the oxidation state of the central metal atom as a Roman numeral inside square brackets: [cobalt(III)].
- Write the names of the ligands in alphabetical order.
- Use prefixes to indicate the number of each ligand, if necessary.
- Use parentheses to group ligands of the same kind, and separate different ligands with commas.
- Add the name of the counterion (in this case, chloride: Cl) outside the square brackets.
Therefore, the IUPAC name of this compound is dichloridobis(amine)cobalt(III) chloride.