Physics

A horizontal force of 45N applied to a crate of mass 9kg is just sufficient to move it. If the crate is now pulled at an angle of 50° to the horizontal, find the force required to move the crate over the horizontal surface. (g=10m/s2)

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  1. Mg = 9*10 = 90 N. = Wt. of crate.
    F = 45 N. = applied force.
    Fs = force of static friction.

    F-Fs = Ma
    45-Fs = 9*0 = 0
    Fs = 45 N.

    F*cos50 = 45
    F = 70 N. = required force.

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  2. The answer is 43.86N

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  3. 08105463644

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