X is partly constant and partly varies with y.when y=3 x=11 and when y=4 x=14. A)find the relationship between x and y. B) fine x when y=10

Solve it for me

I can't sovle it

x = my + b

so, using the two data points,
3m+b = 11
4m+b = 14
I is clear that m=3, so find b and then x(10)

I cant solve it no explanation

Explain to us pls

Good

I don't get, please explain

x=3+2y

To find the relationship between x and y, we need to consider the given information that x is partly constant and partly varies with y.

A) Determining the relationship:
We are given two different instances where x and y are related. Let's consider these data points and observe the pattern:

When y = 3, x = 11
When y = 4, x = 14

From these two points, we can see that as y increases by 1, x is increasing by 3.

So, we can say that for every increase in y by 1 unit, x increases by 3 units. This relationship can be written as:

x = 3y + c

Here, 'c' represents the constant part of x when y has a value of 0 or any other initial value. To find the value of 'c', we can substitute one of the data points into the equation:

11 = 3(3) + c
11 = 9 + c
c = 2

Therefore, the relationship between x and y is given by:

x = 3y + 2

B) Finding x when y = 10:
To find x when y = 10, we can substitute the value of y into the equation we found in part A:

x = 3(10) + 2
x = 30 + 2
x = 32

So, when y = 10, x = 32.

X=11,y=3,a=?,b=?

11=a+b times 3
11=a+3b
:a+3b=11