The ratio of Alex’s toy cars to Jim’s toy cars is 8:3. How many toy cars do they have altogether, if Alex has 40 more cars than Jim?
But Alex has forty MORE. How would 8x-3x be equal to that?
Guys just add 24+64 and you get 88
7x-20=3x+20
4x=40
x=10
subsitute 10 with x
70+30 =100!!!!!!!
It is correct
To solve this problem, we need to set up equations using the given information.
Let's assume that Alex has x toy cars, and Jim has y toy cars.
We are given that the ratio of Alex's toy cars to Jim's toy cars is 8:3. This means that the ratio of x toy cars to y toy cars is also 8:3. So, we can set up the equation:
x/y = 8/3
We are also given that Alex has 40 more cars than Jim. This can be written as:
x = y + 40
Now we have a system of equations. We can use substitution to solve for x and y.
Let's solve the second equation for y:
y = x - 40
Now we substitute this expression for y into the first equation:
x/(x - 40) = 8/3
Cross-multiplying, we get:
3x = 8(x - 40)
Expanding the right side:
3x = 8x - 320
Moving the terms to one side:
5x = 320
Dividing both sides by 5:
x = 320/5
x = 64
Now, substitute this value of x back into the second equation to find y:
y = 64 - 40 = 24
So, Alex has 64 toy cars and Jim has 24 toy cars.
To find the total number of toy cars they have altogether, simply add their individual totals:
64 + 24 = 88
Therefore, Alex and Jim together have 88 toy cars.
Jim has X cars.
Alex has x+40 cars.
(x+40)/x = 8/3.
3x+120 = 8x
8x-3x = 120
X = 24.
x+40 = 24+40 = 64.
Umhh, if Alexa has 40 more, wouldn't the difference between their amounts be 40???
Why don't we solve my equation?
8x - 3x = 40
5x = 40
x = 8
I defined Alex's numbers as 8x , so 64
and I defined Jim's amount as 3x, so 24
doesn't Alex have 40 more than Jim???
Alex has 8x of them
Jim has 3x of them
8x - 3x = 40
carry on