The ratio of Alex’s toy cars to Jim’s toy cars is 8:3. How many toy cars do they have altogether, if Alex has 40 more cars than Jim?

But Alex has forty MORE. How would 8x-3x be equal to that?

Guys just add 24+64 and you get 88

7x-20=3x+20

4x=40
x=10

subsitute 10 with x
70+30 =100!!!!!!!
It is correct

To solve this problem, we need to set up equations using the given information.

Let's assume that Alex has x toy cars, and Jim has y toy cars.

We are given that the ratio of Alex's toy cars to Jim's toy cars is 8:3. This means that the ratio of x toy cars to y toy cars is also 8:3. So, we can set up the equation:

x/y = 8/3

We are also given that Alex has 40 more cars than Jim. This can be written as:

x = y + 40

Now we have a system of equations. We can use substitution to solve for x and y.

Let's solve the second equation for y:

y = x - 40

Now we substitute this expression for y into the first equation:

x/(x - 40) = 8/3

Cross-multiplying, we get:

3x = 8(x - 40)

Expanding the right side:

3x = 8x - 320

Moving the terms to one side:

5x = 320

Dividing both sides by 5:

x = 320/5

x = 64

Now, substitute this value of x back into the second equation to find y:

y = 64 - 40 = 24

So, Alex has 64 toy cars and Jim has 24 toy cars.

To find the total number of toy cars they have altogether, simply add their individual totals:

64 + 24 = 88

Therefore, Alex and Jim together have 88 toy cars.

Jim has X cars.

Alex has x+40 cars.

(x+40)/x = 8/3.
3x+120 = 8x
8x-3x = 120
X = 24.
x+40 = 24+40 = 64.

Umhh, if Alexa has 40 more, wouldn't the difference between their amounts be 40???

Why don't we solve my equation?
8x - 3x = 40
5x = 40
x = 8

I defined Alex's numbers as 8x , so 64
and I defined Jim's amount as 3x, so 24

doesn't Alex have 40 more than Jim???

Alex has 8x of them

Jim has 3x of them
8x - 3x = 40

carry on