A solution is prepared by mixing 1.00g ethanol (C2H5OH) with 100.0g water to give a final volume of 101.mL. Calculate the molarity, mass percent and mole fraction of ethanol in the solution.
Please can I see the answer
M = mols/L.
mols = g/molar mass = 1.00/46 = ? but check those numbers.
M = mols/0.101 L = ?
% w/w (or m/m) = (mass solute/total mass)*100
% = (1.00/101)*100 = ?
mols ethanol = g/molar mass = ?
mols H2O = g/molar mass = ?
Total mols = mols ethanol + mols H2O = ?
Xethanol = mols ethanol/total mols = ?
XH2O = mols H2O/total mols = ?
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To calculate the molarity, mass percent, and mole fraction of ethanol in the solution, we need to know the amount of ethanol and water present in the solution.
Given:
Mass of ethanol = 1.00 g
Mass of water = 100.0 g
Final volume of the solution = 101 mL
First, let's convert the volume of the solution from milliliters to liters:
101 mL = 0.101 L
Now, we can calculate the molarity of ethanol in the solution using the equation:
Molarity (M) = moles of solute / volume of solution in liters
To find the number of moles of ethanol, we need to convert the mass of ethanol to moles using its molar mass.
Molar mass of ethanol (C2H5OH):
C = 12.01 g/mol
H = 1.008 g/mol
O = 16.00 g/mol
So, the molar mass of ethanol (C2H5OH) = (2 * 12.01) + (6 * 1.008) + 16.00 = 46.07 g/mol
Number of moles of ethanol = Mass of ethanol / Molar mass of ethanol
Number of moles of ethanol = 1.00 g / 46.07 g/mol
Now, we can calculate the molarity:
Molarity (M) = 1.00 g / 46.07 g/mol / 0.101 L
Next, let's calculate the mass percent of ethanol in the solution.
Mass percent of ethanol = (Mass of ethanol / Total mass of solution) * 100
Mass percent of ethanol = (1.00 g / (1.00 g + 100.0 g)) * 100
Finally, let's calculate the mole fraction of ethanol in the solution.
Mole fraction of ethanol = Moles of ethanol / Total moles in solution
Total moles in solution = Moles of ethanol + Moles of water
To calculate the moles of water, we need to know its molar mass.
Molar mass of water (H2O) = (2 * 1.008) + 16.00 = 18.02 g/mol
Number of moles of water = Mass of water / Molar mass of water
Number of moles of water = 100.0 g / 18.02 g/mol
Mole fraction of ethanol = Moles of ethanol / (Moles of ethanol + Moles of water)
Now, you can substitute the values into the formulas to calculate the molarity, mass percent, and mole fraction of ethanol in the solution.