Blocks of mass 15, 45, and 135 kg are lined up from left to right in that order on a frictionless surface so each block is touching the next one. A rightward-pointing force of magnitude 28 N is applied to the left-most block.
1.)What is the magnitude of the force that the left block exerts on the middle one?
2.)What is the magnitude of the force that the middle block exerts on the left one?
3)What is the magnitude of the force that the middle block exerts on the rightmost one?
4)Now the position of the right two masses is flipped. What is the magnitude of the force that the middle block exerts on the right block?
Acceleration of system = 20/(15 + 30 + 120), = 0.1212m/sec^2.
1) Force = (ma) = (120 + 30) x 0.1212, = 18.18N.
2) The same.
3) (30 x 0.1212) = 3.636N.
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Now find four
To get the answers to these questions, we can analyze the situation using Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.
1) To find the magnitude of the force that the left block exerts on the middle one, we can consider the forces acting on the left block. There is an external force of 28 N acting on it, and since there is no friction, there are no other horizontal forces. By Newton's third law, the left block exerts an equal and opposite force on the middle block. Therefore, the magnitude of the force that the left block exerts on the middle one is also 28 N.
2) Similarly, to find the magnitude of the force that the middle block exerts on the left one, we consider the forces acting on the middle block. The right block exerts a force on the middle one due to their contact. By Newton's third law, the middle block exerts an equal and opposite force on the left block. Therefore, the magnitude of the force that the middle block exerts on the left one is also 28 N.
3) Now, to find the magnitude of the force that the middle block exerts on the rightmost one, we consider the forces acting on the middle and right blocks. The contact force between the middle and right blocks is equal in magnitude but opposite in direction to the contact force between the left and middle blocks. Since the contact force between the left and middle blocks is 28 N, the magnitude of the force that the middle block exerts on the rightmost one is also 28 N.
4) If we flip the position of the right two masses, the only change will be the direction of the force applied to the right block. The magnitude of the force that the middle block exerts on the right block remains the same. Therefore, the magnitude of the force that the middle block exerts on the right block will still be 28 N.
In summary:
1) The magnitude of the force that the left block exerts on the middle one is 28 N.
2) The magnitude of the force that the middle block exerts on the left one is 28 N.
3) The magnitude of the force that the middle block exerts on the rightmost one is 28 N.
4) The magnitude of the force that the middle block exerts on the right block, even after flipping their positions, is still 28 N.