Select the equation that solves this problem:
Eight coins (dimes and nickels) are worth 60 cents. How many dimes are
there?
d = the number of dimes, while 8-d equals the numbers of nickels, if you multiply the number of each coins by their value ( 10 cents or 5 cents ) and add them, you should get 60
got it
Select the equation that solves this problem:
Eight coins (dimes and quarters) are worth 170 cents. How many dimes are
there?
a. 10d + 25(11 - d) = 170
b. 10d + 25(8 - d) = 170
c. 10d + 5(8 - d) = 60
d. 10d + 5(11 - d) = 60
@seco -
Please post this as a New Question. The math tutors are unlikely to find it here.
To solve this problem, we'll need to set up an equation based on the given information. Let's use the variable "d" to represent the number of dimes.
The value of a dime in cents is 10, and the value of a nickel is 5. Since we have eight coins, the total value in cents can be expressed as:
10d + 5(8 - d) = 60
Let's break down the equation:
10d represents the value of the dimes in cents.
5(8 - d) represents the value of the nickels in cents. Since we have 8 coins in total, we subtract the number of dimes (d) from 8 to get the number of nickels.
60 represents the total value of all the coins.
Now we can simplify the equation and solve for "d":
10d + 40 - 5d = 60
5d + 40 = 60
5d = 20
d = 4
Therefore, there are 4 dimes in the collection of eight coins.