If the concentration of arsenic found in a well is 31.0 ppm, determine the mass of arsenic, in milligrams, in a 341 mL bottle of water from that well.
I remember that 1 ppm = 1 mg/L so 31.0 ppm is 31.0 mg/L. Convert to mg in 341 mL or 31.0 x (341 mL/1000 mL) = ?
341 mL of water has a mass of 341 g
a millionth of that is .341 mg
multiply by 31.0 to find the arsenic
To determine the mass of arsenic in the water, we need to use the given concentration and the volume of water.
The concentration of arsenic is given as 31.0 ppm, which means there are 31.0 grams of arsenic present in 1 million grams (or 1 million milliliters) of water.
First, let's convert the concentration to grams per milliliter (g/mL). Since 1 ppm is equivalent to 1 milligram per liter (mg/L), we can convert ppm to mg/mL by dividing by 1000:
31.0 ppm / 1000 = 0.031 mg/mL
Now, we can calculate the mass of arsenic in the 341 mL bottle of water by multiplying the volume by the concentration:
0.031 mg/mL * 341 mL = 10.571 mg
Therefore, the mass of arsenic in the 341 mL bottle of water is approximately 10.571 milligrams.