Suzy deposits $500 in a savings account with an interest rate of 6% compounded annually. if suzy does not make any additional deposits or withdrawals, how long will it take for suzy to earn at least $95

for y being the time in years

595 = 500 (1 + .06)^y

log(595 / 500) = y log(1.06)

To find out how long it will take for Suzy to earn at least $95, we will need to use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:
A = the amount of money accumulated after time t
P = the principal amount (initial deposit)
r = annual interest rate (as a decimal)
n = number of times interest is compounded per year
t = time in years

In this case, Suzy deposits $500 (P), earns an interest rate of 6% (r = 0.06), compounded annually (n = 1), and wants to find out how long it will take for the amount to be at least $595 ($500 + $95).

Substituting these values into the formula, we get:

595 = 500(1 + 0.06/1)^(1*t)

Now, let's solve for t:

595/500 = (1 + 0.06)^t

1.19 = 1.06^t

Taking the logarithm of both sides, we get:

log(1.19) = log(1.06^t)

t * log(1.06) = log(1.19)

t = log(1.19) / log(1.06)

Using a calculator, we find that:

t ≈ 5.96 years

So, it will take approximately 5.96 years for Suzy to earn at least $95 in interest on her deposit of $500.

$531.8