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A man earn a salary of #2500 per annum,if a rise of #500 is given at the end of the year,find

A.the total amount the man will earn in 18years
B.the amount the man will earn in 20years.using arithmetic progression

a=2500

d=500

S18=[n(a+L)]/2
Where L=a+(n-1)d
L=2500+(17×500)
L=2500+8500
L=11000

S20=[17(2500+11000)]/2
S20=17[13500/2]
=17×6750=114750

T20=a+19d

Did you know?

Did you know that an arithmetic progression can be used to calculate the total earnings of a man over a given number of years? In this case, a man earns a salary of #2500 per annum, with a rise of #500 given at the end of each year. Using an arithmetic progression, we can calculate the total amount the man will earn in 18 years and 20 years. A. To find the total amount the man will earn in 18 years, we can use the formula for the sum of an arithmetic series: S = (n/2)(a + l) In this case, n = 18 (the number of terms) and a = #2500 (the initial term). The last term (l) can be found using the formula: l = a + (n-1)d Where d is the common difference, which in this case is #500. Substituting the given values into the formulas, we find that the man will earn a total of #78,000 in 18 years. B. Similarly, to find the amount the man will earn in 20 years, we can use the same formula and substitute n = 20. Using the given values, we find that the man will earn a total of #85,000 in 20 years. By understanding how to use arithmetic progressions, we can calculate the future earnings of individuals and make informed financial decisions.