In an isosceles triangle is one of the angles 40∘. What values are possible for the outer angles.
This means two angles are the same right and need to total 180? So 40/40/100 or 40/70/70?
looks good to me
Yes, in an isosceles triangle, two angles are equal. Since one of the angles is given as 40 degrees, the remaining two angles must also be equal to each other.
To find the measure of the other angles, we can use the fact that the sum of angles in a triangle is always 180 degrees.
Let's call the other two angles x. Since they are equal, we can express their sum as 2x. And we know that the sum of all three angles is 180 degrees.
So we can write the equation: 40 + 2x = 180
Now, we can solve for x:
Subtracting 40 from both sides: 2x = 180 - 40 --->
2x = 140
Dividing both sides by 2: x = 70
Therefore, the angles of the isosceles triangle could be either 40/70/70 degrees or 40/40/100 degrees.