What is the 68th term of the sequence
7, -2, -11, -20,...?
well, it is clear that
a = 7
d = -9
so, what is a+67d ?
To find the 68th term of the given sequence 7, -2, -11, -20,..., we need to identify the pattern in the sequence first.
From the first term to the second term, we subtract 9. Then, from the second term to the third term, we also subtract 9. Therefore, it seems like the sequence is decreasing by 9 at each step.
To find the nth term of an arithmetic sequence (a sequence with a common difference), we can use the formula:
nth term = first term + (n - 1) * common difference
In this case, the first term (a1) is 7, the common difference (d) is -9, and we want to find the 68th term (n = 68).
Plugging the values into the formula, we get:
68th term = 7 + (68 - 1) * (-9)
Simplifying this equation, we have:
68th term = 7 + 67 * (-9)
68th term = 7 - 603
68th term = -596
Therefore, the 68th term of the sequence 7, -2, -11, -20,... is -596.