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Find the slope-intercept form of the line given that x=-2+3t y=4-6t.

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  1. x=-2+3t , y=4-6t
    solve each one for t

    x = -2 + 3t
    3t = x+2
    t = (x+2)/3

    in the same way:
    t = (4-y)/6

    then: (x+2)/3 = (4-y)/6
    cross-multiply
    6x + 12 = 12 - 3y

    simplify and arrange into the form requested

  2. m = Y/X = (4-6t)/(-2+3t) = -2(-2+3t)/(-2+3t) = -2.
    Y = mx+b
    4-6t = -2(-2+3t)+b
    4-6t = 4-6t+b
    b = 0.
    Y = -2x+0
    Y = -2x.

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