Projectile motion: If a player hits a voley ball 2.35 m from the ground and gives it an initial velocity of Vo= 14 m/s forward and 3.5 m/s upwards.

a) Ignoring air resistance show whether the ball clears the net or not.
b) Similarly, show whether the ball lands inbound on the other side of the court or not.

a. Vo = 14+3.5i = 14.4 m/s.[14o].

Y^2 = Yo^2+2g*h = 0
3.5^2+(-19.6)h = 0
h = 0.625 m. above launching point.
2.35+0.625 = 3 m. above gnd.
The net is app. 2.4 m above gnd.
Range = Vo^2*sin(2A)/g = 14.4^2*sin(28)/9.8 = 9.9 m. = hor. distance.
Therefore, the ball clears the net.

b. 9.9m * 3.3Ft./m = 32.7 Ft.
Distance from net to out-of-bounds line = 30 Ft.
Therefore, the ball does not land inbound.

the height is

y = 2.35 + 3.5t - 4.9t^2
The horizontal distance is x = 14t

without knowing the height of the net, or the length of the court, there is no way to answer the questions.

To determine whether the volleyball clears the net or lands inbound on the other side of the court, we can analyze the projectile motion of the ball using the given initial conditions and known physics equations.

a) To determine if the ball clears the net, we need to find the maximum height it reaches during its trajectory. Let's analyze the motion vertically.

Given:
Initial velocity in the upward direction, Vyo = 3.5 m/s.
Acceleration due to gravity, g = -9.8 m/s² (negative due to gravity pulling downward).
Height of the net, h = 2.35 m.

We can use the following equation for vertical motion to find the time taken for the ball to reach its maximum height:

Vfy = Vyo + gt
0 = 3.5 - 9.8t
t = 0.357 s

Now, using this time value, we can find the maximum height reached by the ball using the following equation:

y = yo + Vyo*t + (1/2)gt²
y = 0 + 3.5*0.357 + (1/2)(-9.8)(0.357)²
y ≈ 1.0872 m

Since the maximum height reached by the ball is 1.0872 m, which is higher than the height of the net (2.35 m), the volleyball will clear the net.

b) To determine if the ball lands inbound on the other side of the court, we need to find the horizontal distance traveled by the ball. Let's analyze the motion horizontally.

Given:
Initial velocity in the forward direction, Vox = 14 m/s.
Time taken, t = 2 * 0.357 s (considering symmetrical motion).
Horizontal distance from the net, d = ?

We can use the following equation for horizontal motion to find the distance traveled:

x = xo + Vox*t
x = 0 + 14 * (2 * 0.357)
x = 10.012 m

The horizontal distance traveled by the ball is approximately 10.012 m. Since this distance is greater than the width of the court, the ball will land inbound on the other side of the court.

Therefore, based on the given initial conditions, the volleyball will clear the net and land inbound on the other side of the court.