If the student needs a 2.0M phosphoric acid solution (H3PO4) and only has 7.14g of it, what is the volume of solution that can be created in mL?
how many moles in 7.14g?
a 2M solution will have half that many liters, right?
Good morning oobleck. Regarding your response, that should be right.
To find the volume of solution that can be created, we need to understand the relationship between the amount of solute (phosphoric acid) and the concentration of the solution.
The concentration of a solution is usually expressed in terms of molarity (M), which is defined as the number of moles of solute per liter of solution.
We are given that the student needs a 2.0M phosphoric acid solution. This means that we need to dissolve 2.0 moles of phosphoric acid in 1 liter (1000 mL) of solution.
To determine the volume of solution that can be created using 7.14g of phosphoric acid, we first need to convert the mass of the solute to moles. To do this, you need to know the molar mass of phosphoric acid (H3PO4).
The molar mass of phosphoric acid is calculated by summing up the atomic masses of each element present:
1 mole of H3PO4 = (3 × atomic mass of H) + (1 × atomic mass of P) + (4 × atomic mass of O)
Now, use the molar mass of phosphoric acid to convert the given mass to moles:
moles of H3PO4 = mass of H3PO4 / molar mass of H3PO4
Once you have the moles of H3PO4, you can calculate the volume of the solution using the following equation:
volume of solution (in liters) = moles of H3PO4 / concentration (in M)
Finally, convert the volume of the solution from liters to milliliters:
volume of solution (in mL) = volume of solution (in liters) × 1000
By following these steps and performing the necessary calculations, you can find the volume of solution that can be created using 7.14g of phosphoric acid.