there are 28 in our class. one day there were 6 times as many present as there were absent.
how many were present?
how many were absent?
how can i make this questions
NO.......
"there were 6 times as many present as there were absent"
number of absent ---- x
number of present ---- 6x
x+6x = 28
7x=28
x = 4
So 4 were absent, and 24 were present.
number present: x
number absent : 28-x
x = 28-x + 6
2x = 34
x = 17
so present = 17, absent = 11
Tote now has posted 2 very wrong answers.
Tote is now in time-out.
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Well, it seems like your class had quite the attendance mystery! Let's see if we can solve it together.
If there were 6 times as many students present as absent, we can represent this with the equation: present = 6 * absent.
We also know that the total number of students in your class is 28. So we can write another equation: present + absent = 28.
Now, let's substitute the first equation into the second equation to solve for the value of "absent": 6 * absent + absent = 28.
Combining like terms, we get: 7 * absent = 28.
To find the value of "absent," we can divide both sides of the equation by 7: absent = 28 / 7.
Dividing, we find that "absent" is equal to 4.
Now, we can substitute this value back into the second equation to solve for the value of "present": present + 4 = 28.
Subtracting 4 from both sides, we get: present = 28 - 4.
So, there were 24 students present and 4 students absent in your class that day. Mystery solved!
Now, as for making the question more entertaining, how about we add a touch of humor? Here's a suggestion:
"In our class of 28 hilarious students, one day, the attendance tricked us all! When the roll was called, there were 6 times more funny beings present than brave souls absent. How many of us proved our comedy skills in class that day, and how many hid from the fun? Solve the mystery, and let the laughter begin!"
To create this type of question, you need to provide the total number of students in the class and the information about the ratio between the number of students present and absent on a specific day. Here is how you can make this question:
In a class of 28 students, there were 6 times as many present as absent on a certain day. Find the number of students present and the number of students absent on that day.
To solve this question, we can use algebraic equations. Let's assume the number of absent students is 'x', and the number of present students is 'y'.
From the given information, we know that "the number of present students is 6 times the number of absent students." Using this, we can write the equation:
y = 6x
We also know that the total number of students in the class is 28, so we can write another equation:
x + y = 28
Now, we have a system of equations. We can solve this system to find the values of 'x' and 'y'.
To solve the system, we can substitute the value of 'y' from the first equation into the second equation:
x + (6x) = 28
Simplifying this equation gives us:
7x = 28
Dividing both sides by 7, we get:
x = 4
Now, we can substitute the value of 'x' back into the first equation to find 'y':
y = 6(4) = 24
Therefore, on that day, there were 24 students present and 4 students absent.