Two people push a box at the same time. A person pushes a 5 kg box with 15 N of force towards the north. Another person pushes the same box with 25 N of force towards the east. What is the net force on this box?
Fx = 25
Fy = 15
F = sqrt(625 + 225) = 29.2 Newtons
direction
tan angle above x (east) axis = Fy/Fx = 15/25
so angle above x axis = 31 degrees
compass angle = 90 - 31 = 59 degrees about northeast by east
To find the net force on the box, we need to combine the forces in both the north and east directions. This can be done using vector addition.
1. Start by drawing a coordinate system, with north as the positive y-direction and east as the positive x-direction.
2. The force applied towards the north is 15 N. Since force is a vector quantity, this can be represented as (0 N, 15 N).
3. The force applied towards the east is 25 N. This can be represented as (25 N, 0 N).
4. Add the two vectors together to find the resultant force. In this case, you add the x-components and the y-components separately.
Adding the x-components: 0 N + 25 N = 25 N
Adding the y-components: 15 N + 0 N = 15 N
5. The resultant force can be represented as (25 N, 15 N), or 25 N towards the east and 15 N towards the north.
Therefore, the net force on the box is 25 N towards the east and 15 N towards the north.
To find the net force on an object, we need to consider the individual forces acting on it. In this case, we have two forces: one towards the north and the other towards the east. Since the forces are acting in different directions, we can't simply add them up algebraically.
To find the net force, we need to use vector addition. We can treat the forces as vectors and add them using the Pythagorean theorem. The net force will be the vector sum of the two forces.
To do this, we break down the forces into their components. Let's call the northward force F1 and the eastward force F2.
F1 = 15 N (north)
F2 = 25 N (east)
To determine the components, we use trigonometry. Since the forces are acting at right angles to each other, we can use the following relationships:
F1_vertical = F1 * sin(θ)
F2_horizontal = F2 * cos(θ)
Here, θ represents the angle between the force and the north direction (which is 90 degrees in this case).
F1_vertical = 15 N * sin(90°) = 15 N * 1 = 15 N (upward)
F2_horizontal = 25 N * cos(90°) = 25 N * 0 = 0 N (no horizontal component)
Since the eastward force has no horizontal component, it doesn't contribute to the net force in the east direction. Therefore, the net force in the east direction is 0 N.
To calculate the net force in the north direction, we add up the vertical components:
Net force (north) = F1_vertical = 15 N
So, the net force on the box is 15 N northwards.