Find the force required to move a 25 kg crate South across the floor (µ = 0.45) at a uniform speed.
f = m * g * µ = 25 * 9.8 * 0.45 ... Newtons
25x9.8x0.45
To find the force required to move the crate, we need to calculate the frictional force acting on it. The frictional force can be calculated using the equation:
Frictional force = coefficient of friction * normal force
The normal force is equal to the weight of the crate, which can be calculated using the equation:
Normal force = mass * gravity
Where:
mass = 25 kg (mass of the crate)
gravity = 9.8 m/s^2 (acceleration due to gravity)
Substituting the values into the equation, we can calculate the normal force:
Normal force = 25 kg * 9.8 m/s^2
Normal force = 245 N
Next, substituting the value of the coefficient of friction (µ = 0.45) and the normal force (245 N) into the equation for frictional force, we can calculate the force required to move the crate:
Frictional force = 0.45 * 245 N
Frictional force = 110.25 N
Therefore, the force required to move the 25 kg crate South across the floor at a uniform speed is 110.25 N.
To find the force required to move the crate, we need to use the formula for frictional force. The formula is:
Frictional Force = Coefficient of Friction * Normal Force
The normal force is the force perpendicular to the surface that the object is resting on. In this case, since the crate is on the floor, the normal force is equal to the weight of the crate, which is given by the formula:
Normal Force = mass * gravitational acceleration
Given that the mass of the crate is 25 kg and the gravitational acceleration is approximately 9.8 m/s^2, we can calculate the normal force:
Normal Force = 25 kg * 9.8 m/s^2 = 245 N
Next, we can substitute the coefficient of friction and the normal force into the formula for frictional force:
Frictional Force = 0.45 * 245 N
Finally, we can calculate the frictional force:
Frictional Force = 110.25 N
Therefore, the force required to move the 25 kg crate south across the floor at a uniform speed is approximately 110.25 N.