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Write the complex number 6-6i in polar form with argument θ between 0 and 2π.

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Hannah

  1. 6-6i
    magnitude = √(36 + 36) = √72 = 6√2
    angle:
    tanθ = -6/6 = -1 , where θ is in 4th quadrant of the Argand plane
    θ = 315° or 7π/4 radians

    6 - 6i = 6√2(cos(7π/4) + i sin(7π/4))
    sometimes shortened to 6√2 cis (7π/4)

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    Reiny

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