Five kilograms of ice cubes are moved from the freezing compartment of a refrigerator into a deep freezer. The refrigerator’s freezing compartment is kept at -4.0 degrees Celsius. The deep freezer is kept at -17 degrees Celsius. How much heat does the freezer’s cooling system remove from the ice cubes?

q = heat difference = mass ice x specific heat ice x (Tfinal-Tinitial)

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To calculate the amount of heat removed, we use the formula:

Q = m * c * ΔT

Where:
Q = Amount of heat removed
m = Mass of the ice cubes = 5 kilograms
c = Specific heat capacity of ice = 2.09 J/g°C (or 2090 J/kg°C)
ΔT = Change in temperature = -17°C - (-4°C) = -13°C

Now we can substitute the values into the equation:

Q = 5 kg * 2090 J/kg°C * -13°C
Q = -135,850 J

Therefore, the freezer's cooling system removes 135,850 J of heat from the ice cubes.

To calculate the amount of heat that the freezer's cooling system removes from the ice cubes, you need to use the heat transfer equation:

Q = m * c * ΔT

Where:
Q represents the amount of heat transferred
m is the mass of the object (in this case, the ice cubes)
c is the specific heat capacity of the object
ΔT is the change in temperature

First, we need to calculate the change in temperature (ΔT). The initial temperature of the ice cubes is -4.0 degrees Celsius, and after being moved to the deep freezer, the final temperature is -17 degrees Celsius.

ΔT = final temperature - initial temperature
ΔT = -17 degrees Celsius - (-4.0 degrees Celsius)
ΔT = -17 degrees Celsius + 4.0 degrees Celsius
ΔT = -13 degrees Celsius

Next, we need to determine the specific heat capacity of ice. The specific heat capacity of ice is 2.09 J/g°C.

Now, we can calculate the amount of heat transferred (Q) using the given mass of the ice cubes, which is 5 kilograms.

Q = m * c * ΔT
Q = 5 kg * 2.09 J/g°C * (-13°C)

Note: The units of mass must be consistent with the specific heat capacity, so we convert 5 kg to grams (1 kg = 1000 g).

Q = 5000 g * 2.09 J/g°C * (-13°C)
Q = -135,650 J

Therefore, the freezer's cooling system removes approximately 135,650 joules (J) of heat from the ice cubes.