A patient takes vitamin pills each day he must have at least 270 are you a vitamin E 10 MG of vitamin B one and 120 MG of vitamin C he can choose pick between till one which contains 150 are you a vitamin A to Angie of vitamin B one and 20 MG of vitamin C and pill to which contain 30 IU of vitamin D two MG of vitamin B one and 30 MG and vitamin C who won cost $.10 until two cars $.20 complete parts a and B below
If there are x,y,z pills in the vitamin order named (E,B,C) then
x+y+z >= 270
Other than that, the question is garbled and unintelligible. I suggest you repost, stating each set of data in one line, and then stating clearly at the end just what you need to do.
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To find out which combination of pills is more cost-effective, let's break down the information.
Given:
Patient needs at least 270 units of vitamins per day.
Option 1: Pill A
- Vitamin E: 10 MG
- Vitamin B1: 1 unit
- Vitamin C: 120 MG
Option 2: Pill B
- Vitamin A: 150 IU
- Vitamin B1: 2 units
- Vitamin C: 20 MG
- Vitamin D: 30 IU
Costs:
Pill A cost: $0.10
Pill B cost: $0.20
Now let's calculate the total cost and the total units of each vitamin in each option:
Option 1 (Pill A):
- Cost: $0.10
- Total units of Vitamin E: 270 * (10 MG) = 2700 MG
- Total units of Vitamin B1: 270 units
- Total units of Vitamin C: 270 * (120 MG) = 32,400 MG
Option 2 (Pill B):
- Cost: $0.20
- Total units of Vitamin A: 270 * (150 IU) = 40,500 IU
- Total units of Vitamin B1: 270 * 2 = 540 units
- Total units of Vitamin C: 270 * (20 MG) = 5,400 MG
- Total units of Vitamin D: 270 * (30 IU) = 8,100 IU
Now, compare the cost and the total units of each vitamin in both options. Then determine which option gives more vitamins per dollar spent.