Sulfur dioxide (SO2) is an unwelcome result
of burning soft coal in power plants. Some
of the SO2 ends up as sulfuric acid in acid
precipitation. The net reaction is
2 SO2(g) + O2(g) + 2 H2O(ℓ) −→ 2 H2SO4(ℓ)
What mass in grams of SO2 is needed to react with 1444 g of O2?
To determine the mass in grams of SO2 needed to react with 1444 g of O2, we first need to find the stoichiometric ratio between SO2 and O2.
Looking at the balanced equation:
2 SO2(g) + O2(g) + 2 H2O(ℓ) → 2 H2SO4(ℓ)
We can see that the stoichiometric ratio between SO2 and O2 is 2:1.
So for every 2 moles of SO2, we need 1 mole of O2.
Now we can calculate the number of moles of O2 using its given mass. The molar mass of O2 is 32 g/mol.
Number of moles of O2 = Mass of O2 / Molar mass of O2
= 1444 g / 32 g/mol
= 45.125 mol (approximately)
Since the stoichiometric ratio between SO2 and O2 is 2:1, we need half the number of moles of O2 to react with SO2.
Number of moles of SO2 = Number of moles of O2 / 2
= 45.125 mol / 2
= 22.5625 mol (approximately)
Finally, we can calculate the mass of SO2 using its molar mass. The molar mass of SO2 is 64 g/mol.
Mass of SO2 = Number of moles of SO2 × Molar mass of SO2
= 22.5625 mol × 64 g/mol
= 1444 g (approximately)
Therefore, 1444 grams of SO2 is needed to react with 1444 g of O2.
To find the mass of SO2 needed to react with 1444 g of O2, we need to use stoichiometry, which is a method of converting between different substances in a chemical reaction.
In the given balanced equation:
2 SO2(g) + O2(g) + 2 H2O(ℓ) → 2 H2SO4(ℓ)
We can see that the stoichiometric ratio between SO2 and O2 is 2:1. This means that for every 2 moles of SO2, we need 1 mole of O2 to completely react.
First, we need to calculate the number of moles of O2 in 1444 g using its molar mass. The molar mass of O2 is 32 g/mol.
Number of moles of O2 = mass / molar mass
Number of moles of O2 = 1444 g / 32 g/mol
Number of moles of O2 = 45.125 mol
According to the stoichiometric ratio, 2 moles of SO2 react with 1 mole of O2. Therefore, the number of moles of SO2 needed can be calculated as:
Number of moles of SO2 = (2/1) * number of moles of O2
Number of moles of SO2 = (2/1) * 45.125 mol
Number of moles of SO2 = 90.25 mol
Finally, we can calculate the mass of SO2 using its molar mass, which is 64 g/mol.
Mass of SO2 = number of moles of SO2 * molar mass
Mass of SO2 = 90.25 mol * 64 g/mol
Mass of SO2 = 5776 g
Therefore, the mass of SO2 needed to react with 1444 g of O2 is 5776 grams.