Specific Heats for Several Common Metals J g^-1 °C^-1
AI - 0.903 Cu- 0.385 Fe- 0.449 K- 0.757 Pb- 0.128 Zn- 0.388
b) Which metal requires more heat per gram to warm it up? Explain your answer.
c) Which metal would be the warmest if an equal mass of each metal absorbed the same amount of heat? Explain.
d) How many joules of energy are needed to heat a 125 gram chunk of copper from an initial temperature of 10.0 °C to a final temperature of 95.0 °C?
e) If the same quantity of heat from your answer to (c) is used to heat a 125 gram piece of aluminum initially at 10.0 °C, what will be the final temperature?
f) Does the final temperature you calculated in (d) for the aluminum make sense? Explain.
sorry if this was repost but i really need help :(
heat=mass*specific heat*change in temp
for the same mass, same change in tem, higher specific heat takes more heat.
c) change heat= heat/(mass*specheat) so the one with the smallest specheat gets hotter.
d)heat= mass*specHeatcopper*changetimsp
work it out.
b) To determine which metal requires more heat per gram to warm it up, we need to compare the specific heats of the metals. The specific heat represents the amount of heat energy required to raise the temperature of one gram of the substance by one degree Celsius.
Comparing the specific heats provided:
- AI has a specific heat of 0.903 J/g·°C
- Cu has a specific heat of 0.385 J/g·°C
- Fe has a specific heat of 0.449 J/g·°C
- K has a specific heat of 0.757 J/g·°C
- Pb has a specific heat of 0.128 J/g·°C
- Zn has a specific heat of 0.388 J/g·°C
From these values, AI (Artificial Intelligence) requires the most heat per gram to warm it up, as it has the highest specific heat of 0.903 J/g·°C.
c) To determine which metal would be the warmest if an equal mass of each metal absorbed the same amount of heat, we need to compare the specific heats again. Since all metals have the same mass and absorb the same amount of heat, we are looking for which metal can increase its temperature the most.
Considering the provided specific heats:
- AI has a specific heat of 0.903 J/g·°C
- Cu has a specific heat of 0.385 J/g·°C
- Fe has a specific heat of 0.449 J/g·°C
- K has a specific heat of 0.757 J/g·°C
- Pb has a specific heat of 0.128 J/g·°C
- Zn has a specific heat of 0.388 J/g·°C
In this case, K (Potassium) would be the warmest metal, as it has the highest specific heat of 0.757 J/g·°C and can increase its temperature the most when the same amount of heat is absorbed.
d) To calculate the amount of energy (in joules) needed to heat a 125 gram chunk of copper from an initial temperature of 10.0 °C to a final temperature of 95.0 °C, we can use the formula:
Energy = mass × specific heat × temperature change
Given:
- Mass (m) = 125 grams
- Specific heat (s) for Cu = 0.385 J/g·°C
- Initial temperature (T1) = 10.0 °C
- Final temperature (T2) = 95.0 °C
Temperature change (ΔT) = T2 - T1 = 95.0 °C - 10.0 °C = 85.0 °C
Plugging these values into the formula:
Energy = 125 g × 0.385 J/g·°C × 85 °C
Energy = 4118.75 Joules
Therefore, 4118.75 joules of energy are needed to heat a 125 gram chunk of copper from an initial temperature of 10.0 °C to a final temperature of 95.0 °C.
e) To find the final temperature of a 125 gram piece of aluminum when the same quantity of heat from part (c) is used, we can use the formula:
Energy = mass × specific heat × temperature change
Given:
- Mass (m) = 125 grams
- Specific heat (s) for AI (Artificial Intelligence) = 0.903 J/g·°C
- Energy = 4118.75 Joules
- Initial temperature (T1) = 10.0 °C
We need to solve for the final temperature (T2).
First, rearrange the formula to solve for temperature change (ΔT):
ΔT = Energy / (mass × specific heat)
Plugging in the values:
ΔT = 4118.75 J / (125 g × 0.903 J/g·°C)
ΔT ≈ 36.32 °C
Then, calculate the final temperature:
T2 = T1 + ΔT
T2 = 10.0 °C + 36.32 °C
T2 ≈ 46.32 °C
Therefore, the final temperature of the 125 gram piece of aluminum, when the same quantity of heat is used, will be approximately 46.32 °C.
f) The final temperature calculated in part (d) for aluminum does not make sense because aluminum was not part of the initial information or provided specific heats. Therefore, the calculation for the final temperature of aluminum is not valid.