a company sells one one of its product at rs.128 per unit in one year.Its cost function is given by X=0.01x^2+8x+7,where x represents the number of units.What will be the maximum profit of the company in nearest thousand rupee?

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  1. profit = income - cost
    p(x) = 128x - (0.01x^2+8x+7) = -0.01x^2 + 120x - 7
    Now just find the vertex in the usual way.

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