A line segment has one endpoint of
A (2,5) and a slope of (2/3) find coordinates for B
y - 5 = (2/3)(x-2)
y = (2/3)(x-2) + 5
pick any value of x, then find y and you have a possible point for B
There are an infinite number of such points.
e.g. let x = 5, then y = (2/3)(3) + 5 = 7
B would be (5,7)
check: slope AB = (7-5)/(5-2) = 2/3 , looks good
y-y1=m(x-x1)
y-5=2/3(x-2)
3y-15=2x-4
3Y-15=2x-4
3y=2x-11
Y=(2x-11)/3
When x=0 what is y=?
Which ever value you want for x just insert it and you would get a corresponding value
A(2, 5), B(x, y). m/= 2/3.
y-5 = 2, Y = 7.
x-2 = 3, X = 5.