At the start of a lab, you and your partner are given 250.0 g of aluminum chloride. The lab tells you to react it with silver nitrate to produce silver chloride and aluminum nitrate. At the start of a lab, you and your partner are given 250.0 g of aluminum chloride. The lab tells you to react it with silver nitrate to produce silver chloride and aluminum nitrate. How much silver chloride is produced in grams?
AlCl3 + 3AgNO3 ==> Al(NO3)3 + 3AgCl
mols AlCl3 = grams/molar mass = 250.0/? = about 2 but that's an estimate.
Using the coefficients in the balanced equation, convert mols AlCl3 to mols AgCl. That will be about 2 x (3 mols AgCl/1 mol AlCl3) = about 6 mols AgCl. Now convert that to grams. g = mols x molar mass = about 6 x 143 or so = ? Remember my numbers are estimates. You need to redo all of the calculations.