The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process.

2Cu2O(s)+O2(g)โŸถ4CuO(s)

The change in enthalpy upon reaction of 70.64 g Cu2O(s) is โˆ’72.08 kJ .

Calculate the work, ๐‘ค , and energy change, ฮ”๐‘ˆrxn , when 70.64 g Cu2O(s) is oxidized at a constant pressure of 1.00 bar and a constant temperature of 25โˆ˜ C .

Note that ฮ”๐ธrxn is sometimes used as the symbol for energy change instead of ฮ”๐‘ˆrxn .

To calculate the work, ๐‘ค, and energy change, ฮ”๐‘ˆrxn, we need to use the information given and relevant equations.

First, let's calculate the number of moles of Cu2O(s) used in the reaction:

Molar mass of Cu2O = 2 * Atomic mass of Cu + Atomic mass of O = (2 * 63.55 g/mol) + 16.00 g/mol = 143.10 g/mol

Number of moles of Cu2O = Mass of Cu2O / Molar mass of Cu2O
= 70.64 g / 143.10 g/mol
โ‰ˆ 0.493 mol

Now, let's calculate the work using the equation:
๐‘ค = โˆ’Pฮ”๐‘‰

Since the pressure, P, is given as 1.00 bar and the reaction is taking place at constant pressure, we need to determine the change in volume, ฮ”๐‘‰.

To find ฮ”๐‘‰, we use the ideal gas law equation:
PV = nRT

Since the pressure, P, and temperature, T, are given, we need to determine the initial and final volumes, V.

The initial volume, V_initial, can be obtained from the number of moles and molar volume of Cu2O:
V_initial = n_initial * V_molar

The final volume, V_final, can be obtained from the number of moles and molar volume of CuO after the reaction:
V_final = n_final * V_molar

Given that the molar volume at STP (standard temperature and pressure) is 22.4 L/mol, we have:
V_initial = 0.493 mol * 22.4 L/mol
V_final = 4 * 0.493 mol * 22.4 L/mol

Now we can calculate ฮ”๐‘‰:
ฮ”๐‘‰ = V_final - V_initial

Finally, we can calculate the work:
๐‘ค = โˆ’P * ฮ”๐‘‰

Next, let's calculate the energy change, ฮ”๐‘ˆrxn, using the equation:
ฮ”๐‘ˆrxn = ฮ”๐ปrxn - ๐‘ค

Given that ฮ”๐ปrxn is -72.08 kJ, we can substitute the values to find the energy change.

Remember to convert the temperature to Kelvin (25ยฐC + 273.15 = 298.15 K) in order to use the ideal gas law equation.

By following these steps and performing the necessary calculations, you should be able to find the values of work, ๐‘ค, and energy change, ฮ”๐‘ˆrxn.