A 60 Watt light bulb draws 0.5 A of current.
a. What is the voltage across the light bulb?
b. What is the resistance of the light bulb?
To find the voltage across the light bulb, we can use Ohm's Law. Ohm's Law states that voltage (V) is equal to current (I) multiplied by resistance (R). Therefore, to find the voltage (V), we need to know the current (I).
Given:
Current (I) = 0.5 A
Using Ohm's Law:
V = I * R
We also know that power (P) can be calculated by multiplying voltage (V) and current (I). The power formula is:
P = V * I
Given:
Power (P) = 60 W
Current (I) = 0.5 A
Using the power formula, we can rearrange it to solve for voltage (V):
P = V * I
V = P / I
a. To find the voltage (V), we can substitute the given values into the formula:
V = 60 W / 0.5 A
V = 120 V
Therefore, the voltage across the light bulb is 120 volts.
b. To find the resistance (R), we can use Ohm's Law:
V = I * R
Substituting the values we know:
120 V = 0.5 A * R
To solve for R, we divide both sides of the equation by 0.5 A:
R = 120 V / 0.5 A
R = 240 ohms
Therefore, the resistance of the light bulb is 240 ohms.
To find the voltage across the light bulb, we can use Ohm's Law, which states that voltage (V) is equal to the current (I) multiplied by the resistance (R).
a. To find the voltage (V), we need to know the current (I) and the resistance (R). In this case, the current is given as 0.5 A. However, we don't have the resistance directly.
To calculate the resistance, we can use the equation for power (P) which is equal to the current (I) multiplied by the voltage (V). Rearranging the equation to solve for resistance (R), we get R = V / I.
Given that the power of the light bulb is 60 Watts and the current is 0.5 Amps, we can rearrange the equation to solve for the voltage (V).
P = I * V
60 Watts = 0.5 A * V
V = 60 Watts / 0.5 A
V = 120 Volts
Therefore, the voltage across the light bulb is 120 Volts.
b. Now that we know the voltage (V) and the current (I), we can use Ohm's Law to calculate the resistance (R).
R = V / I
R = 120 V / 0.5 A
R = 240 Ohms
Therefore, the resistance of the light bulb is 240 Ohms.
power in watts = Volts * current in amps
60 = V * 0.5
V = 120 Volts (seems about right)
V = i R
R = V/i