Think of a number square it, add 2 times the original number. The result is 80 find the number
no
It is elementary
To find the number, we can set up an algebraic equation based on the given information.
Let's say the number is represented by the variable "x."
According to the given information, we need to square the number, which gives us x^2. Then, we need to add 2 times the original number, which gives us 2x.
The equation can be written as: x^2 + 2x = 80.
Now, let's solve this equation to find the value of x:
Step 1: Rearrange the equation: x^2 + 2x - 80 = 0.
Step 2: Factor the quadratic equation or use the quadratic formula to solve for x. In this case, the equation can be factored as (x + 10)(x - 8) = 0.
Step 3: Set each factor equal to zero and solve for x:
For x + 10 = 0, x = -10.
For x - 8 = 0, x = 8.
Therefore, there are two possible values for x: x = -10 or x = 8.
x^2 + 2x = 80
which two factors of 80 differ by 2?