The points P and Q have coordinates (4,0) and (9,0) respectively.
The points P’ and Q’ have coordinates (4,4) and (7,8) respectively.
Write down the length of PQ
did you plot P and Q? They lie on the x-axis, 5 units apart!
To find the length of PQ, we can use the distance formula. The distance formula is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
Using the coordinates of points P(4,0) and Q(9,0), we can plug these values into the formula:
d = √((9 - 4)^2 + (0 - 0)^2)
= √(5^2 + 0)
= √(25)
= 5
Therefore, the length of PQ is 5 units.
To find the length of PQ, we can use the distance formula in a Cartesian coordinate system.
The distance formula is given by:
d = √[(x2 - x1)^2 + (y2 - y1)^2]
where (x1, y1) and (x2, y2) are the coordinates of the two points.
For PQ, the coordinates are (4,0) and (9,0). Plugging these values into the formula, we have:
d = √[(9 - 4)^2 + (0 - 0)^2]
= √[5^2 + 0^2]
= √25
= 5
Therefore, the length of PQ is 5 units.